(x^2+4-2x)(x-1)=0

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Solution for (x^2+4-2x)(x-1)=0 equation: 


Simplifying
(x2 + 4 + -2x)(x + -1) = 0

Reorder the terms:
(4 + -2x + x2)(x + -1) = 0

Reorder the terms:
(4 + -2x + x2)(-1 + x) = 0

Multiply (4 + -2x + x2) * (-1 + x)
(4(-1 + x) + -2x * (-1 + x) + x2(-1 + x)) = 0
((-1 * 4 + x * 4) + -2x * (-1 + x) + x2(-1 + x)) = 0
((-4 + 4x) + -2x * (-1 + x) + x2(-1 + x)) = 0
(-4 + 4x + (-1 * -2x + x * -2x) + x2(-1 + x)) = 0
(-4 + 4x + (2x + -2x2) + x2(-1 + x)) = 0
(-4 + 4x + 2x + -2x2 + (-1 * x2 + x * x2)) = 0
(-4 + 4x + 2x + -2x2 + (-1x2 + x3)) = 0

Combine like terms: 4x + 2x = 6x
(-4 + 6x + -2x2 + -1x2 + x3) = 0

Combine like terms: -2x2 + -1x2 = -3x2
(-4 + 6x + -3x2 + x3) = 0

Solving
-4 + 6x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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